I think the answer is E. I think the rules are as follows:

- No circle can be chosen more than once;
- The next circle should be the one with the least inner circles;
- If the choice of no. inner circles is the same, then the next circle should be the one linked to the fewest lines.


So, starting at J, we have the option of either K, E or I. E is immediatedly discounted as it has an inner circle. That leaves K and I, neither of which have an inner circle. K is lined to 5 lines, I to 2, so we select I.

By the time we get to A, there are five choices : F, B, C, D, E. We've already been to F, so we can't choose that one again. B and D both have two inner circles, so we discount them. That leaves C and E. C is linked to 7 lines, E to 6, so the final choice is E.

Of course, I could be wrong, but that's how I see it. Let me know what you think!